5p^2-29p+36=0

Solution for 5p^2-29p+36=0 equation:

5p^2-29p+36=0

a = 5; b = -29; c = +36;
Δ = b2-4ac
Δ = -292-4·5·36
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-11}{2*5}=\frac{18}{10}
=1+4/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+11}{2*5}=\frac{40}{10}
=4
$